Harlowe syntax help

Hotdogger · October 2016

So I'm trying to make a statement that only displays one option if the variable is less than 10, otherwise if the variable is 10 or above it displays another option. But for some reason it only ever displays the options under the else statement. I'm using Harlowe, the problem probably has something to do with the syntax and my lack of knowledge.

(if: $gold is < 10)[ "Gambling is not my forte, but I'll watch."
]
(else:)[ "Gambling is not my forte, but I'll watch."

"Maybe just a little bit."(Lose 10 gold pieces)
]

If anyone could help me out I'd really appreciate it.

TheMadExile · October 2016

You're combining two different operators "is" and "<" (less-than), which you don't want to do. Just use the less-than operator here.

Hotdogger · October 2016

TheMadExile wrote: »

You're combining two different operators "is" and "<" (less-than), which you don't want to do. Just use the less-than operator here.

Thanks for the help, I have a lot to learn about proper syntax.

Khaloodxp · October 2016

if you're new to harlowe (which apparently you are) read it's manual here http://twine2.neocities.org/

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Harlowe syntax help

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